Question

 In a trapezium ABCD, AD=BC=17cm. DE is perpendicular to AB and CF is perpendicular to AB. Also, DE=8cm and AB=40cm. Find AE.​

Answer 1

Answer:

AD = 6.66 cm

Step-by-step explanation:

In parallelogram ABCD, we have given AB=10cm, AE=8cm, and CF=12cm.

⇒ AB=DC=10cm [Opposite sides of parallelogram are equal]

⇒ Lets find out area of parallelogram with height AE and base DC.

⇒ Area of parallelogram ABCD=b×h

⇒ Area of parallelogram ABCD=DC×AE

⇒ 10×8

∴ Area of parallelogram ABCD=80cm

2

--- ( 1 )

⇒ Now, to find area of parallelogram let CF be the height and AD will be base.

⇒ Area of parallelogram ABCD=CF×AD

⇒ 80=12×AD [From ( 1 )]

⇒ AD=

12

80

∴ AD=6.66cm

Answer 2

Answer:

in triangle ADE

Hypotenuse =17cm

perpendicular =8cm

and we get base 15cm by pythagorous theorum's formulae

then AE= 40cm-15cm= 25cm