Question

in a trapezium abcd, angle a : angle d =7:2 and and angle b: angle c = 4:5. find the angles of the trapezium​

Answer 1

Answer:

angles of the trapezium are

angle A: 140 degrees

angle B: 80 degrees

angle C: 100 degrees

angle D: 40 degrees

Step-by-step explanation:

given

angle A : angle D = 7:2

angle B : angle C = 4:5

now, let angle A = 7x, angle B =4x, angle C = 5x, angle D = 2x

We know that sum of all interior angles of any quadrilateral is 360 degrees

therefore, angle A+ angle B+ angle C+ angle D= 360 degrees

substitute the angle values in terms of x

7x+ 4x+ 5x+ 2x= 360 degrees

18x= 360 degrees

x= 20 degrees

now the angles are

angle A: 20X7= 140 degrees

angle B: 20X4= 80 degrees

angle C: 20X5= 100 degrees

angle D: 20X2= 40 degrees

Hope you liked this explanation.