Question

In a trapezium abcd seg ab parallel to seg DC seg bd perpendicular to seg ad seg AC perpendicular seg bc if ad=15 bc =15 and ab=25 find area of quadrilateral abcd

Answer 1

Hey dear,

we can find out the area of triangle ADB
so height for this triangle wud be equal to the height of trapezium.

so we get height = 12cm.
now we can easily get to CD=7cm

and we know area of trapezium =1/2*(AB+CD)*HEIGHT

NOW,1/2*(25+7)*12 = 192 cm.

how to get CD=7 cm

when we will drop two perpendicular lines from D to AB as point E and from C to AB as point F.

So,we can see that EF = CD (as the line drawns were perpendicular)

Now In triangleADE,
We know AD=15 and DE=12
So we can easily find AE = 9

Similarly from triangleBCF,
we will get BF = 9cm

therefore,EF = AB -(AE+BF) = 25 - 18 =7cm.

Hope it Helpful to uh.. :)

Answer 2

Answer:

Step-by-step explanation: