Question

In a trianglabc, angle a=100 degree and ab=ac, find angle b and angel c​

Answer 1

SOLUTION

AB = AC

∠B = ∠C         

In △ABC,

∠A+∠B+∠C = 180°

∠A = 100°

∠B=40°

Therefore,

∠B =∠C = 40°

Answer 2

make a triangle ABC. <A= is equals to hundred degree <B = <C therefore <a + angle b + angle c is equals to 180 degree by angle sum propert = angle b + angle C +100 <c=<b. a <b is equals to 80 degree C is equals to b/c = b=40 degree <c=40