in a triangle A=x B=3x and C=y.if 3y-5x=30 prove that the triangle is right angled. with all the steps
Answers
here,A=x,B=3x,C=y. Sum of triangles= x+3x+y 180= 4x+y ----(1) 180-4x=y ----(2) Also ,3y-5x=30 -----(3) Substituting the value of (2) in (3) 3(180-4x)-5x=30 540-12x-5x=30 -17x= 30-540 17x= 510 x= 30 ----(4) 4x+y=180 From (4) we get, 4*30+y=180 y= 180-120 y=60 by solving , one of the angles is 90degrees , hence proved that the triangle is right-angled triangle.
Answer:
Step-by-step explanation:
here,A=x,B=3x,C=y. Sum of triangles= x+3x+y 180= 4x+y ----(1) 180-4x=y ----(2) Also ,3y-5x=30 -----(3) Substituting the value of (2) in (3) 3(180-4x)-5x=30 540-12x-5x=30 -17x= 30-540 17x= 510 x= 30 ----(4) 4x+y=180 From (4) we get, 4*30+y=180 y= 180-120 y=60 by solving , one of the angles is 90degrees , hence proved that the triangle is right-angled triangle.
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