In a triangle abc 2a=4b=12c find angles
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2a=4b=12c=x
=> 2a=x
a =x/2
=> 4b=x
b =x/4
=> 12c=x
c =x/12
=>x/2+x/4+x/12=180
=>6x+3x+x/12=180
=>10x=180×12
=>x=180×12/10
=>x=216
a=x/2=216/2=108°
b=x/4=216/4=54°
c=x/12=216/12=18°
HOPE IT HELPS...!!
=> 2a=x
a =x/2
=> 4b=x
b =x/4
=> 12c=x
c =x/12
=>x/2+x/4+x/12=180
=>6x+3x+x/12=180
=>10x=180×12
=>x=180×12/10
=>x=216
a=x/2=216/2=108°
b=x/4=216/4=54°
c=x/12=216/12=18°
HOPE IT HELPS...!!
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