In a triangle ABC, 2B is two thirds of LA and ZC is 20 more than LA. Find the measures of the three
angles of the triangle
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Let angle A be x
Therefore, angle B = 2/3x
Therefore, angle C = 20+x
Sum of all the angles of the triangle = 180°
Therefore, ATQ,
x+ 2/3x + x+20 = 180°
=) 2x +2/3 x = 180-20
=) 8/3x = 160°
=) x = 160× 3/8
=) x = 60°
Therefore,
angle A = 60°
angle B = 2/3 × 60 = 40°
angle C = 60+20 = 80°
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