Question

In a triangle ABC, /_A = 120° and
/_B = 2/_C. Find /_B and /_ C.

Answer 1

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Answer 2

In a triangle ABC
we know that the some of all three angle of a Δ is 180
and we know that /_B =2/_C
Now, According to question
120° + /_B + /_C = 180°
2/_C + /_C = 60°
3/_C = 60°
/_C = 20°
then,
/_ B = 2 × 20 = 40°

Justification :-
120° + 20° + 40°=180°

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