Question

In a triangle ABC, A=130° and AB=AC. Find angles B and C​

Answer 1

$\huge \mathbb \blue{ANSWER}$

This ∆ABC is an isosceles triangle. In this kind of triangle, two of the sides are equal..

$ab = ac \: \: (given)$

Let ∆ABC be a triangle such that :

$a = 130° \: and \: b = c = x \: (let)$

NOW USING ANGLE SUM PROPERTY OF ∆

$a + b + c = 180°$

$130° + x + x = 180°$

$130° + 2x = 180°$

$2x = 180° - 130°$

$2x = 50°$

$x = \frac{50°}{2}$

$x = 25°$

So measure of each of remaining two angles is 25°.

Answer 2

Answer:

This ∆ABC is an isosceles triangle. In this kind of triangle, two of the sides are equal..

ab = ac \: \: (given)ab=ac(given)

Let ∆ABC be a triangle such that :

$a = 130° \: and \: b = c = x \: (let)a=130°andb=c=x(let)$

NOW USING ANGLE SUM PROPERTY OF ∆

a + b + c = 180°a+b+c=180°

130° + x + x = 180°130°+x+x=180°

130° + 2x = 180°130°+2x=180°

2x = 180° - 130°2x=180°−130°

2x = 50°2x=50°

$x = \frac{50°}{2}x=$

So measure of each of remaining two angles is 25°.