Question

In a triangle ABC, a=2, b = 3 and sinA= 2/3, then B is equal to​

Answer 1

Answer:

B = 90 degree

Step-by-step explanation:

given :

a= 2

b= 3

sin A =2/3

in triangle ABC

using sine rule

sin A/a=sin B/b=sin C/c= k

sin B=b * sin A/a

sin B= 3*(2/3)/2

on solving

sin B = 1

sin B = sin 90

therefore

B= 90 degree

Answer 2

In ∆ABC a=2,b=3 and sinA=2/3

By applying sine law

a/sinA = b/sinB = c/sinC

$→ \frac{2}{2/3} = \frac{3}{sinB}→sinB=1⇒B= \frac{\pi}{2} .$