in a triangle ABC,a-2b+c=0.the value ofcot(A/2).cot(C/2).
Answers
Answered by
7
side a+c=2b
deviding both side by 2
a/2. +c/2. =b
now.
a+b+c=180
a/2+b/2+c/2=90
put a/2+c/2=b
hence b+b/2=90
3b=180
hence b=60...
deviding both side by 2
a/2. +c/2. =b
now.
a+b+c=180
a/2+b/2+c/2=90
put a/2+c/2=b
hence b+b/2=90
3b=180
hence b=60...
ankush93:
ans ky h uska
3 hoga answer
make me brainleast plz
haan yrr
ha
pr apne pura solve q nh kiya
kuch kaam tha
kkk
a + c = 2b
A C Cot cot
2 2
= s(s a) s(s c)
(s b)(s c) (s a)(s b)
= s 2s a b c 3b 3
s b 2s 2b a b c 2b b
A C Cot cot
2 2
= s(s a) s(s c)
(s b)(s c) (s a)(s b)
= s 2s a b c 3b 3
s b 2s 2b a b c 2b b
Similar questions