In a triangle abc a=5 b=7 and sin a = 3/4 how many such triangles are possible
Answers
Answered by
7
Given that
a=5, b=7, sin A =3/4
As we know
sin A/a = sin B/b
=> 3/4×5 = sin B/7
=> sin B = 21/20
Which is not possible because its value is greater than one.
Similar questions