In a triangle ABC, A is 50° more than B and C is 20° less than B. what are the angles of a triangle ?
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Let angle B is x,
According to the question :
=> angle A = 50 + angle B
angle A = 50 + x
=> angle C = angle B - 20
angle C = x - 20
We Know, sum of all angles of a triangle is 180
angle A + angle B + angle C = 180
=> x + 50 + x + x - 20 = 180
=> 3x + 30 = 180
=> 3x = 150
=> x = 50°
Hence, angle B = x = 50°
angle A = 50 + 50 = 100°
angle C = 50 - 20 = 30°
According to the question :
=> angle A = 50 + angle B
angle A = 50 + x
=> angle C = angle B - 20
angle C = x - 20
We Know, sum of all angles of a triangle is 180
angle A + angle B + angle C = 180
=> x + 50 + x + x - 20 = 180
=> 3x + 30 = 180
=> 3x = 150
=> x = 50°
Hence, angle B = x = 50°
angle A = 50 + 50 = 100°
angle C = 50 - 20 = 30°
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