Question

In a triangle ABC a side AB is 80 cm and its perimeter is 170and angle ABC is 60 then find its smallest side

Answer 1

45 cm is the length of the smallest side

Answer 2

Answer:

17 cm

Step-by-step explanation:

Let the remaining side be a and b respectively.

Since the perimeter = 170 cm and one of the side is 80, then

a + b = 90  ---- (1)

Based on cosine rule,

cos 60 = ( a² + 80² - b² ) /  ( 2 x a x 80  )

1/2 = ( a² + 80² - b² ) /  ( 160 a  )  --- (2)

Solving (1) and (2) we get,

a = 17, b = 73

So the smallest side = 17 cm