In a triañgle abc ab =15 bc=13 ac=14. Find the area of abc and hence its altitude on ac
Answers
Answered by
0
s=a+b+c÷2
s=15+14+13/2
s=21
area=root (s (s-a)(s-b)(s-c))
=root21 (6)(7)(8)
area=root7056=84
h=area/side
h=84/14=6
s=15+14+13/2
s=21
area=root (s (s-a)(s-b)(s-c))
=root21 (6)(7)(8)
area=root7056=84
h=area/side
h=84/14=6
Similar questions