Question

In a triangle ABC, AB = 15 cm, BC = 13 cm and AC = 14 cm. Find area of triangle ABC and hence its altitude on AC.

Answer 1

Hi Friend !!!

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AC = 14cm , AB = 15cm , BC = 13 cm

S = a+b+c/2

= 14+15+13/2

= 42/2

= 21

Area of triangle

$\sqrt{s(s - a)(s - b)(s - c)} \\ \\ = \sqrt{21(21 - 13)(21 - 14)(21 - 15) } \\ \\ = \sqrt{21(8)(7)(6)} \\ \\ = \sqrt{7,056} \\ \\ = 84$
Area of triangle = 84cm²

Hope it helps u :-)