in a triangle ABC,AB=30,BC=26,AND AC =28cm .find the area of triangle ABC and its altiudeir AC
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please mark it as a brainlest answer.
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s=30+26+28/2
s=42
area=√s(s-a)(s-b)(s-c)
area=√42(42-30)(42-26)(42-28)
area=√42(12)(16)(14)
area=√112896
area=336 cm²
altitude AC= 28 cm
s=42
area=√s(s-a)(s-b)(s-c)
area=√42(42-30)(42-26)(42-28)
area=√42(12)(16)(14)
area=√112896
area=336 cm²
altitude AC= 28 cm
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