Question

in a triangle ABC ,AB =AC and <A = 80° .Find the values of X,<A and <B.​

Answer 1

Given:-

• ABC is a Triangle
• AB = AC
• ∠BAC = 80°

To Find:-

• Value of ∠ABC & ∠ACB

Solution:-

WKT,

✯ Angles Opposite To Equal Sides Are Equal.

So, ∠ABC = ∠ACB = x°

$→\;{\sf{∠BAC+∠ABC+∠ACB = 180°}}$

☞ Sum of Angles in a ∆le are Supplementary.

$→\;{\sf{80°+x+x = 180°}}$

$→\;{\sf{2x = 180°-80°}}$

$→\;{\sf{x = \frac{100°}{2}}}$

$➝\;{\bf{x = 50°}}$

AnSweR:-

Value of ∠ABC & ∠ACB ◕➜ $\Large{\red{\mathfrak{50°\:✓}}}$

Hope It Helps You ✌️