In a triangle ABC ,AB=AC, D and E are the points on the side AB and AC respectively such that BD=CE.show that ∆dbc is congruent to ∆ecb
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Step-by-step explanation:
Since we know that angle opposite to equal sides are equal....and DB= EC (given)
therefore, angle 1 = 2
therefore we get three things equal in ∆DBC and ∆ EBC
BC = BC, cause it's common..
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