Question

In a triangle abc, AB is 15 cm,BC is 14 cm,AC is 13cm find the area of triangle and find its height

Answer 1

Answer:

In ∆ABC, AB = 15 cm , BC = 13 cm and AC = 14 cm.

↪ By Heron's formula ,

↪  

= √S (S–A) (S–B) (S–C)

= √21 (21–15) (21–13) (21–14)

= √21 (6) (8) (7)

= √7056

Therefore, the area of ∆ABC is 84cm² and its altitude on AC is 12 cm.

Step-by-step explanation:

Answer 2

Answer:

area = 84 cm2. height = 12 cm

Step-by-step explanation:

According to heron's formula

area = √s(s-a)(s-b)(s-c)

s= (a+ b+ c)/2

so, s= (15+14+13)/2 =21 cm

area= √21(21-15)(21-14)(21-13)

= √21*6*7*8

= 84cm2

also, area = 1/2 * base * height.

(if base is taken to be 14 cm)

84 = 1/2 * 14 * h

then, h = 12 cm