Question

In a triangle abc ac = bc and angle c = 110 degrees find angles s a and b

Answer 1

Answer:

a and b =35 degree

Explanation:

In ABC,Angle C=110.As AC=BC,So by using the rule of ANGLES OPPOSITE TO EQUAL SIDES ARE EQUAL,AngleA=AngleC.Next by using ANGLE SUM PROPERTY,

A+B+C EQUALS 180,

110+B+C=180

B+B=70

2B=70

B=70÷2

=35 DEGREE

Answer 2

Given - Angle C and same sides

Find - Angle a and b

Solution - Angle a and angle b is 35°.

The given triangle has two equal sides so it is an isosceles triangle. So, remaining two angles will be same as well.

Hence, let the remaining angle be x.

x + x + 110 = 180

2x = 180 - 110

2x = 70

x = 70/2

x = 35°

Hence, angle a and angle b is 35°.