Question

in a triangle ABC, AD and BE, the bisectors of angle A and angle B, respectively, intersect at point F. if the measurement of angle A = 70 and the measurement of angle B = 80, what is the measure of angle AFB. ( i really need this answer, I'm lost)

Answer 1

Answer:

Here is your answer :

Step-by-step explanation:

Given - In ∆ABC,

<A=70°

<B=80°

To prove -<AFB = ?

Proof -As we know that ,

AD is the bisector of <A and ,

BE is the bisector of <B.

So, In ∆AFB,

<FAB =1/2 <A

=1/2×70

= 35°

Similarly,

<ABF =1/2 <B

=1/2×80

= 40°

In ∆ ABF, (By angle sum property )

<FAB+ <ABF +<ABF. =180 °

35+ 40+<AFB =180°

75 + <AFB = 180 °

<AFB = 180 -75

<AFB = 105 °

:. measure of the angle AFB is 105. °

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