in a triangle ABC, AD is a median. Prove that (AB + BC + AC) > 2 AD.
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In tri. ABD
AB + BD > AD --- (i) [Sum of 2 sides of tri. is always greater than the third side]
AC + DC > AD ---- (ii) [""]
Adding eqn. i & ii
AB + BD + DC + AC > 2 AD
AB + BC + AC > 2AD
Hence , Proved
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