Question

In a triangle ABC, AD is angle bisector of angle BAC and angle BAD =60. What is the length of AD?

Answer 1

The length of $AD$ is $\frac{1}{2}AB\ cm$

Step-by-step explanation:

Given,

In a $\triangle ABC$, $AD$ is angle bisector of $\angle BAC$ and $\angle BAD =60\ degree$.

In figure Consider $\triangle ABD$,

Where $AB$ is hypotenuse,$AD$ is base,$BD$ is height and angle between hypotenuse and base is $60\ degree$.

So,

$Cos(60)=\frac{AD}{AB}$

⇒ $AD=AB\times cos(60)$

∴ $AD=\frac{1}{2}AB$

So, The length of $AD$ is $\frac{1}{2}AB\ cm$