in a triangle ABC ,AD perpendicular to BC such that AD square =
BD x CD prove that triangle ABC is a right angle at A
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Answered by
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draw a line parllel to bc passing through A angle d is 90 then angle a is intrrior angle therefor it eill be 45 & 45 which is equal to 90
Answered by
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AD2= BD x CD
AB2=AD2+BD2
AC2=AD2+CD2
on adding
AB2+AC2=2AD^2+BD2+CD2
AB2+AC2=2BDCD+BD2+CD2
AB2+AC2=(BD+CD)^2
by using (a+b)^2
AB2+AC2=BC2
By converse of Pythagoras
angle A= 90°
hope it helps
AB2=AD2+BD2
AC2=AD2+CD2
on adding
AB2+AC2=2AD^2+BD2+CD2
AB2+AC2=2BDCD+BD2+CD2
AB2+AC2=(BD+CD)^2
by using (a+b)^2
AB2+AC2=BC2
By converse of Pythagoras
angle A= 90°
hope it helps
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