Math, asked by ranjith12, 1 year ago

in a triangle ABC ,AD perpendicular to BC such that AD square =
BD x CD prove that triangle ABC is a right angle at A

Answers

Answered by san85
1
draw a line parllel to bc passing through A angle d is 90 then angle a is intrrior angle therefor it eill be 45 & 45 which is equal to 90
Answered by Rahulsingh131
0
AD2= BD x CD

AB2=AD2+BD2
AC2=AD2+CD2

on adding

AB2+AC2=2AD^2+BD2+CD2

AB2+AC2=2BDCD+BD2+CD2

AB2+AC2=(BD+CD)^2
by using (a+b)^2
AB2+AC2=BC2

By converse of Pythagoras

angle A= 90°

hope it helps
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