Question

in a triangle ABC angel B is 90 degree, if AB=BC find AC:BC​

Answer 1

Answer:

AC:BC=√2:1

Step-by-step explanation:

in right angle triangle ABC

AC²=AB²+BC²

since AB=BC

AC²=2×AB²

AC=√2AB or √2BC

$\frac{ac}{bc} = \frac{ \sqrt{2bc} }{bc} \: \: \: \: \: = \sqrt{2}$

hence AC/BC=√2/1

hope this will help you

Answer 2

Answer:-

ABC is a triangle with AB=BC and angle B=90°

let the side AB be x then BC=AB=x

By Pythagoras theorum:-

(AC)²= (AB)²+ (BC)²

(AC)²= X²+X²

(AC)²= 2X²

AC=√2X²

AC=X√2

Now,

AC:BC

X√2:X

√2:1, is the ratio

thanks:)✌️