In a triangle ABC,angle A =x,angle B=3x-2,angle C =y and angle C -angle But=9 find the three angles
Answers
Answer:
angle A=25
angle B=73
angle C=82
Step-by-step explanation:
By angle sum property of triangle-
angle A+angle B+angle C=180
x+3x-2+y=180
=4x-2+y..................................(1)
y-(3x-2)=9
or y-3x+2=9...............….....................(2)
eq.(1)-eq.(2)
4x-2+y-(y-3x+2)=180-9
4x-2+y-y+3x-2=171
7x-4=171
7x=175
x=25............answer angle A
angle B=3*25-2=73
angleC=180-(25+73)
= 180-98
=82
Answer:
In a triangle ABC :
angle A + angle B + angle C = 180
--------------(angle sum property of triangle)
• angle C - angle B = 9
y - (3x-2) = 9
y = 9+(3x-2)
y = 7+3x
•x + (3x-2) + y = 180
x + (3x-2) + (7+3x) = 180
x + 3x + 3x -2+7 = 180
7x = 175
x = 25°
• y = 7 + 3×25
y = 82°
The respective angles of the triangle ABC are ;
Angle A = x = 25°
Angle B = 3x-2 = 73°
Angle C = y = 82°
hope this helped,
plzzz mark as brainliest ..................... !