In A triangle ABC angle ACB = 90°, BC is to produced to D such that angleDAB = 90°.
Prove that AB square = BC×BD.
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it is proved
Step-by-step explanation:
adjacent sides of right angled triangle is height and base, and opposite side of right angle is hypotenuse.
first from right angled triangle ABC , find height base and hypotenuse.
again we have to find height base and hypotenuse from right angled triangle ADB.
hence proved.
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