Math, asked by kiransihmar25, 3 months ago

In a triangle ABC, angle B is an acute angle and AD is perpendicular to BC. Prove that
i. AC2=AB2+BC2
-2BC*BD
ii. AB2+CD2=AC2+BD2

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Answered by shraddha663

0

Step-by-step explanation:

In a triangle ABC, angle B is an acute angle and AD is perpendicular to BC. Prove that

i. AC2=AB2+BC2

-2BC*BD

ii. AB2+CD2=AC2+BD2

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