In a triangle ABC, angle B is equal to angle C. Prove that the perpendiculars from the midpoint if BC to AB and AC are equal.
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Answer:
Let DE and DF be perpendiculars from D on AB and AC respectively.
In order to prove that AB=AC, we will prove that ΔBDE≅ΔCDF.
In these two triangles, we have
∠BEF=∠CFD=90
∘
BD=CD [∵ D is the mid - point of BC ]
DE=DF [Given ]
So, by RHS congruence criterion, we obtain
ΔBDE≅ΔCDF
⇒∠B=∠C
⇒AC=AB
⇒ΔABC is isosceles.
Step-by-step explanation:
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Answered by
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Answer:
☆ ABC is isosceles. ☆
Step-by-step explanation:
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