Question

In a triangle ABC, angle BAC = 90 degree and AD is perpendicular to BC . Then which one is true and why? :-
BD.CD = BC2
BD.CD = AD2
AB.AC = BC2
AB.AC = AD2

Answer 1

option B is correct
this can be easily solved by similarity

Answer 2

Answer:

Option (b) BD. CD = AD^2.

Step-by-step explanation:

(b) BD. CD = AD^2

∵ ∠BAC = 90°

and AD ⊥ BC

∴ ∆ DBA ~ ∆ DAC (AA similarly)

AD / DC = BD / AD

∴ AD^2 = BD × DC.

@Genius