Question

In a triangle ABC angle BAC is 90, AD is the bisector of angle BAC and DE is perpendicular to AC. Prove that DE*(AB+AC)= AB*AC​

Answer 1

Step-by-step explanation:

given,

In ∆ABC in which angle BAC is 90, AD is the bisector of angle BAC and DE is perpendicular to AC

To prove

DE(AB+AC)=AB×AC

Prove,