In a triangle ABC,
Angle C = 3B= 2( A+ B).
Find all the angles
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In a triangle ABC angle C =3 angle B = 2 (angle A+ angle B). What are the three angles?
C = 2(A+B)
C = 3B, or
2(A+B) = 3B, or
2A+2B=3B, or
B=2A.
C =2(A+2A) = 6A
A+2A+6A = 180 or 9A = 180.
Or A = 20 deg. B = 40 deg, C = 120 deg
C = 2(A+B)
C = 3B, or
2(A+B) = 3B, or
2A+2B=3B, or
B=2A.
C =2(A+2A) = 6A
A+2A+6A = 180 or 9A = 180.
Or A = 20 deg. B = 40 deg, C = 120 deg
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