In a triangle ABC, angle C is 9 degrees more than angle B, and angle B is 2 degrees less than three times angle A. Find the angles of the triangle.
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Angle a=x Angle b=3x-2 Angle c=3x-2+9 x+3x-2+3x-2+9=180 7x+5=180 7x=175 x=25(angle A) Angle b=73 Angle c=82
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let angle a be x
let angle b be 3x-2
and angle c be 3x-2+9 =3x+7
adding all the angles a,b and c we know that total is 180 degree
so,x +3x-2+3x+7=180 or 7x +5= 180 or 7x =175 or x = 25 therefore angle a=25 ,b=73 and c=82 degrees
let angle b be 3x-2
and angle c be 3x-2+9 =3x+7
adding all the angles a,b and c we know that total is 180 degree
so,x +3x-2+3x+7=180 or 7x +5= 180 or 7x =175 or x = 25 therefore angle a=25 ,b=73 and c=82 degrees
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