In a triangle ABC BD is perpendicular to AC,BC=60 and BD=36,Find the area of ABC
Answers
CORRECT QUESTION :
In a triangle ABC BD is perpendicular bisector of AC . BC=60 and BD=36,Find the area of ABC
Answer:
area ( ∆ ABC ) = 1728 cm²
Step-by-step explanation:
GIVEN :
A ∆ ABC with BD perpendicular to AC.
BC = 60 cm ,
Perpendicular to AC, BD = 36 cm
We get a right angle ∆ BDC right angled at D
In rt. ∆ BDC ,
We have Perpendicular BD = 36 cm
Hypotenuse BC = 60 cm
As , Base or rt. ∆ = √(Hypotenuse ² - Perpendicular ²)
So, Base DC = √(60² - 36²) = 48 cm
So, DC is 48 cm.
As no other data given let's assume
BD bisects AC
So, AC = 2 DC = 2 x 48 = 96 cm
We know that;
Area of a traingle = ½ x Base x Height
So, area ( ∆ ABC ) = ½ x AC x BD
= ½ x 96 x 36 cm²
= 1728 cm²
Hence, area ( ∆ ABC ) = 1728 cm²