In a triangle ABC ,D and E are point on AB and AC respectively such that AD = AE and DB = EC. Prove that DE is parallel to BC.
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Step-by-step explanation:
Given, AD×EC=AE×DB
∴
DB AD = EC AE
By Coverse of basic Proportionality theorem, which states that
''If a line divides two lines of a △ in same ratio, then line is parallel to Third side.''
DE∥BC
Hence, proved.
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