Question

in a triangle abc d is a point on side ab and e is a point on side ac such that angle ade = angle abc, ad=2cm, bd=3cm, ae=3 cm find ce

pls dont spam
​

Answer 1

Answer:

in triangle ABC

given that angle ADE=angle ABC

therefore DE || BC( since corresponding angles are equal )

now AD/DB=AE/EC (by bpt)

,2/3=3/EC

EC = 9/2

EC = 4.5

Answer 2

Given:

A triangle ABC,

AB have d point.

AC have e point.

The angles are ∠ADE = ∠ABC

AD = 2CM, BD = 3CM, AE = 3CM

To find: CE = ?

Explanation:

We get

DE ║ BC [By using corresponding angle property]

$\frac{AD}{DB}=\frac{AE}{EC}$

$\frac{2}{3}=\frac{3}{EC} \\\\EC=\frac{9}{2}\\\\EC = 4.5$