Question

In a triangle ABC, DE is parallel to BC. AD = 3 cm, AE = 8 cm and EC = 12 cm. Find AB​

Answer 1

In a ∆ABC, DE is parallel to BC .... Given

Using Basic Proportionality Theorem,

$\bold{ \frac{AD}{DB} = \frac{ AE}{EC} }$

$\bold{ \frac{3}{DB} = \cancel \frac{8}{12} }$

$\bold{ \frac{3}{DB} = \frac{2}{3} }$

$\bold{DB = \frac{3 \times 3}{2} }$

$\bold{DB = \frac{9}{2} }$

$\bold{DB = 4.5}$

$\bold{AB = AD + DB}$

$\bold{AB = 3 + 4.5}$

$\bold{AB = 7.5}$

Step-by-step explanation:

$\huge{ \color{aqua}{hope \: it \: helps \: you}}$