In a triangle ABC, equation of side BC is x – y = 0. Circumcenter and orthocenter of the triangle
are (2, 3) and (5, 8) respective. Equation of the circumcircle of the triangle is
Answers
Answered by
5
Answer:
Step-by-step explanation:
Reflection of orthocenter P(5,8) in BC(x−y=0) will lie on circumcircle.
Clearly P₁ = (8,5). Thus, the equation of circumcircle with center O(2,3) and passing through P(8,5) is
(x−2)² +(y−3)² = ( 8 − 2)² + ( 5 − 3 )²
i.e, x ²+y² − 4x − 6y− 27=0
i hope it's help you
Attachments:
Similar questions