Math, asked by dodiyadhruvrajsinh20, 10 months ago

In a triangle ABC, equation of side BC is x – y = 0. Circumcenter and orthocenter of the triangle

are (2, 3) and (5, 8) respective. Equation of the circumcircle of the triangle is​

Answers

Answered by Anonymous
5

Answer:

Step-by-step explanation:

Reflection of orthocenter P(5,8) in BC(x−y=0) will lie on circumcircle.

Clearly P₁ = (8,5). Thus, the  equation of circumcircle with center O(2,3) and passing through P(8,5) is

(x−2)²  +(y−3)² = ( 8 − 2)² + ( 5 − 3 )²

 i.e, x ²+y²  − 4x − 6y− 27=0

i hope it's help you

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