Question

in a triangle ABC equation of side BC is x-y=0circum centre of the triangle are (2,3) and (5,8) respectively.Equation of circum circle of the triangle is​

Answer 1

Step-by-step explanation:

Reflection of orthocenter P(5,8) in BC(x−y=0) will lie on circumcircle.

Clearly P

1

≡(8,5). Thus, the equation of circumcircle with center O(2,3) and passing through P(8,5) is

(x−2)

2

+(y−3)

2

=(8−2)

2

+(5−3)

2

i.e, x

2

+y

2

−4x−6y−27=0

solution