in a triangle ABC having AD is a medium and ar triangle ABD=20m find the ar triangle ABC
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We know that a median divides the ∆into two equal parts
so, ∆ABD=∆ACD
∆ABC=∆ABD +∆ACD
∆ABC=∆ABD+∆ABD
∆ABC=2(∆ABD)
∆ABC=2(20m²)
∆ABC=40m²
so, ∆ABD=∆ACD
∆ABC=∆ABD +∆ACD
∆ABC=∆ABD+∆ABD
∆ABC=2(∆ABD)
∆ABC=2(20m²)
∆ABC=40m²
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