In a triangle abc, i is the in centre and angle a is 80, find angle bic
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Answer:
Step-by-step explanation:
Suppose triangle abc is in a circle,
then i is the centre of the circle,
So, angle bic is a central angle,
angle bac is inscribed in arc bc,
angle bac = 1/2 m(arc bc)
80 = 1/2 m(arc bc)
80x2 = m(arc bc)
m(arc bc) = 160*
m(arc bc) = angle bic,
Angle bic = 160*
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