In a triangle ABC, if /_A - /_B = 33° and /_B - /_C = 18°, then /_B is
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Answer:
In triangle ABC
a - b = 33
a = 33 + b----1
b - c = 18
c=b-18---2
Now in triangle abc by angle sum property
a + b + c = 180
33 + b + b + b - 18 = 180
(by 1 and 2)
15 + 3b = 180
3b = 180 - 15
3b = 165
b = 165/3
b = 55
Now put value of b in eq. 1 and 2
a - b = 33
a - 55 = 3
a = 33 + 55
a = 88
b - c = 18
55 - c = 18
c=55-18
c = 37
Your answer is:
a = 88
b = 55
c = 37
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