In a triangle ABC, if AB+BC=10cm, BC+CA=12cm, CA+AB=16cm, what is its perimeter?
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AB+BC+CA
AB+bc= 10
bc+ca=12
ca+ab=16
10+12+16/2=19
AB+bc= 10
bc+ca=12
ca+ab=16
10+12+16/2=19
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