in a triangle ABC if ab is equal to AC and angle b is equal to 65 degree find angle C and Angle A
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Given: ABC is a triangle where AB =AC, angle b=65 degree.
To find: angle C,angle A
In triangle ABC,AB=AC (given)
therefore, angle b=angle c (angles opposite to equal sides of a triangle are equal)
therefore angle c=65 degree.
angle a= 180-(65+65) degree
=180- 130 degree
=50 degree
Hence, angle a=50 degree and angle c = 65 degree.
To find: angle C,angle A
In triangle ABC,AB=AC (given)
therefore, angle b=angle c (angles opposite to equal sides of a triangle are equal)
therefore angle c=65 degree.
angle a= 180-(65+65) degree
=180- 130 degree
=50 degree
Hence, angle a=50 degree and angle c = 65 degree.
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1
Answer:
Step-by-step explanation:
AB=AC . SO ANGLE B=ANGLE C THEREFORE ANGLE C=65.
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