In a triangle ABC , if angle A +angle B = 108 degree ,angle B +angle C =130 degree find angle A , angle B , and angle C .
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∠A+∠B=108° → equation 1
∠B+∠C=130° → equation 2
Adding equation 1 and 2 we get,
∠A+2∠B+∠C=238° → equation 3
and we know that : ∠A+∠B+∠C=180° → equation 4
∴ Subtracting equation 4 from 3 we get;
∠B=58°
∴∠A=50° (from equation 1)
and ∠C=72° (from equation 2)
∴ ∠A=50°,∠B=58°,∠C=72°
∠B+∠C=130° → equation 2
Adding equation 1 and 2 we get,
∠A+2∠B+∠C=238° → equation 3
and we know that : ∠A+∠B+∠C=180° → equation 4
∴ Subtracting equation 4 from 3 we get;
∠B=58°
∴∠A=50° (from equation 1)
and ∠C=72° (from equation 2)
∴ ∠A=50°,∠B=58°,∠C=72°
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