in a triangle abc, <a+<b=110degree and <c+<a=135 degree. find<a.
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given,
a + b = 110
c + a = 135
we know that sum of all angles of triangle is 180
so, a+b+c=180
a+b=110. (given)
110 + c = 180
c = 180-110
c=70
also c+a=135. (given)
putting c= 70 we get,
70+a=135
a=135-70
a=65
i hope it helps....
a + b = 110
c + a = 135
we know that sum of all angles of triangle is 180
so, a+b+c=180
a+b=110. (given)
110 + c = 180
c = 180-110
c=70
also c+a=135. (given)
putting c= 70 we get,
70+a=135
a=135-70
a=65
i hope it helps....
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