Question

In a triangle abc, pq is a straight line parallel to ac, such that area abc: area pbq = 3:1then cb:cq is equal to​

Answer 1

Answer:

CB/CQ = √3

Step-by-step explanation:

In a triangle abc, pq is a straight line parallel to ac, such that area abc: area pbq = 3:1then cb:cq is equal to​

PQ || AC

=> ΔBPQ ≅ ΔBAC

area abc: area pbq = 3: 1

in Similar Triangles

Area Ratio ∝ Side Ratio²

=> 3/1  = (CB/CQ)²

=> CB/CQ = √3

Answer 2

Answer:√3(√3+1)/2

Step-by-step explanation:

As we know from the question both ∆abc and ∆pqb are similar triangles

Now (∆abc area/∆pqb area)=(bc/bq)^2

(3/1)=(bc/bq)^2

(bc/bq)=√3/1

Let bc=√3x , bq=x

But we need bc/cq

cq=bc-bq

=√3x-x

=X(√3-1)

Now bc/cq=√3x/(√3-1)x

=√3/(√3-1)

To get the another answer divide and multiply the above result with (√3+1)

Then bc/cq =√3(√3+1)/2