Question

In a triangle ABC,prove that AB+BC+AC >2AB

Answer 1

triangle se BC+BC = AB
PROVE 2AB=2AB

Answer 2

Given equation is BC+CA> AB and it is adding AB on the both side  of inequality

then you can get  AB+BC+>AB+AB

AB+BC+CA>2AB

Hence the given equation it get solve and this answer will be right  answer.

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