in a triangle ABC right angled at A, AB=5 cm and AC=12 cm. If AD perpendicular BC then find AD.
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bc=13
ac^2=cd.bc
12^2=CD.10
cd=144/13
ab^2=bd.bc
5^2=bd.13
bd= 25/13
ad^2=144/13*25/13
ad =12*5/13
ad=60/13
ac^2=cd.bc
12^2=CD.10
cd=144/13
ab^2=bd.bc
5^2=bd.13
bd= 25/13
ad^2=144/13*25/13
ad =12*5/13
ad=60/13
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